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const2013 [10]
4 years ago
13

Circle C is shown. Secants A D and D J intersects at point D outside of the circle. Secant A D intersects the circle at point B

and secant D J intersects the circle at point E. Angle D is 37 degrees and the measure of arc B E is 38 degrees. Secants A G and J G intersect at point G outside of the circle. Secant A G intersects the circle at point F and secant J G intersects the circle at point H. Angle G is 32 degrees.
In circle C, what is mArc F H?


31°

48°

112°

121

Mathematics
1 answer:
maksim [4K]4 years ago
5 0

Answer: mArc\ FH=48\°

Step-by-step explanation:

The missing figure is attached.

Observe the figure.

By definition:

m\angle BDE=\frac{1}{2}(mArc\ AJ- mArc\ BE)

You can identify that:

m\angle BDE=37\°\\\\mArcBE=38\°

Substitute values and solve for the arc AJ:

37\°=\frac{1}{2}(mArc\ AJ- 38\°)\\\\2(37\°)+38\°=mArc\ AJ\\\\mArc\ AJ=112\°

By definition:

m\angle FGH=\frac{1}{2}(mArc\ AJ- mArc\ FH)

Since:

m\angle FGH=32\°

You can substitute values and solve for the Arc FH:

32\°=\frac{1}{2}(112\°- mArc\ FH)\\\\2(32\°)-112\°=-mArc\ FH\\\\mArc\ FH=48\°

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Image attachment below, Algebra 1 stuff
chubhunter [2.5K]
I know you didn't want an explanation, but I'll give you one anyway.
So, for a function, when you have f(5) = , then you'll put that 5 in for all of the x's in the function. 

The first batch of problems gave you the equation f(x) = \frac{x}{2} + 3. Now, plug in the numbers given for s and solve.

1. f(5) = <span>\frac{x}{2} + 3   Plug in 5 for x
</span>         = \frac{5}{2} + 3   Make three into a fraction over 2
         = \frac{5}{2} + <span>\frac{6}{2}   Add
         = </span><span><span>\frac{11}{2}

</span>2. f(-4) = </span><span>\frac{x}{2} + 3   Plug in -4 for x
           = </span><span>\frac{-4}{2} + 3   Divide -4 by 2
           = -2 + 3   Add
           = 1

For the next set, you have g(x) = x</span>² + 1.

3. Let's split this up. Solve the first equation, then the second, and then put         the answers together to solve it.

g(4) = x² + 1   Plug in 4 for x
       = 4² + 1   Square
       = 16 + 1   Add
       = 17

g(3) = x² + 1   Plug in 3 for x
       = 3² + 1   Square
       = 9 + 1   Add
       = 10

Now, put the two together.

g(4) + g(3) =    Substitute in the answers you just got.
      17 + 10 =    Add
                  = 27         

4. g(-1) = x² + 1      Substitute in -1 for x
            = (-1)² + 1   Square
            = 1 + 1        Add
            = 2

5. g(-6) = x² + 1       Plug in -6 for x
             = (-6)² + 1   Square
             = 36 + 1      Add
             = 37

For the last set, we have h(x) = x² + 7 and k(x) = 4x - 5. We'll have to pay close attention to the starting variables here.

6. h(-6) = x² + 7       Plug in -6 for x
             = (-6)² + 7   Square
             = 36 + 7      Add
             = 43

k(4) = 4x - 5     Plug in 4 for x
       = 4(4) - 5   Multiply
       = 16 - 5      Subtract
       = 11

Put the two answers into the final equation.

h(-6) + k(4) =    Substitute in the answers you got
       43 + 11 =    Add
                   = 54

7. k(10) = 4x - 5       Plug in 10 for x
            = 4(10) - 5   Multiply
            = 40 - 5      Subtract
            = 35

h(2) = x² + 7   Plug in 2 for x
       = 2² + 7   Square
       = 4 + 7     Add
       = 11

Now, put those into the equation.

k(10) - h(2) =    Plug in the answers you got
       35 - 11 =    Subtract
                  = 24

8. For this one, it wants you to add h(x) and k(x). We don't need to plug anything into the equations this time because they're both already solved for x! So, you can just set this up like a standard find-x equation.

(x² + 7) + (4x - 5) =
    x² + 7 + 4x - 5 =   Combine like terms (7 and -5)
         x² + 2 + 4x =    Reorder so the variables come first
                            = x² + 4x + 2

  
4 0
3 years ago
Read 2 more answers
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Answer:

Step-by-step explanation:

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