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2 years ago

How long is ⅓ of 3 hours?

Mathematics

2 answers:

Nina [5.8K]2 years ago

8 0

Answer:

1/3 of 3 hours should be 20 minutes

andreev551 [17]2 years ago

3 0

Answer: 1 hour

Step-by-step explanation:

(1/3)(3) = 1 hour

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One out of 3 gym members say they spent 5 hours per week at the gym. If there are 150 people working out at the gym, how many wi

lana [24]

Answer: 50

Step-by-step explanation:

From the question, we are informed that 1/3 of gym members say they spent 5 hours per week at the gym.

Assuming there are 150 people working out at the gym, the number of people that'll most likely spend 5 hours at the gym this week will be calculated by multiplying 1/3 by 150. This will be:

= 1/3 × 150

= 50 people

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

Which choice is equivalent to the expression below √-12

kondaur [170]

Answer:

Step-by-step explanation:

using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$ , hence

$\sqrt{-12}$

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2 years ago

Read 2 more answers

A test is used to assess readiness for college. In a recent year, the mean test score was 20.3 and the standard deviation was 4

Vlada [557]

Answer:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$

$High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is higher tor equal to 2.

For this case we have the mean and the deviation given:

$\mu = 20.3$

$\sigma = 4.9$

And we can find the limits in order to consider values as significantly low and high like this:

$Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5$