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3 years ago

5

GEOMETRY Help !! Which term describes the red curve in the figure below?

1 answer:

AleksandrR [38]3 years ago

7 0

It is an elipse
D is the answer

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Graph the set of points. Which model is most appropriate for the set?

Andrew [12]

The model most appropriate is answer choice: Quadratic

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3 years ago

For a circle of raduis 6feet, find the arc length of a central angle of 6

murzikaleks [220]

Length of a circumference=2πr
r=radius=6 feet.
lengt of this circumference=2π6 feet=12π feet.

1 circumference=360º; then:

360º-------------------12π feet
6º---------------------- x

360º * x=6º * 12π feet
x=(6º * 12π feet) / 360º=π/30 feet (≈0,105 feet).

Solution: π/30 feet

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3 years ago

PLEASE HELP THIS IS DUE BY TOMORROW

Bezzdna [24]

Answer:b

Step-by-step explanation:

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3 years ago

4. Gloria the grasshopper is working on her hops.

aivan3 [116]

The path that Gloria follows when she jumped is a path of parabola.

The equation of the parabola that describes the path of her jump is $\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}$

The given parameters are:

$\mathbf{Height = 20}$

$\mathbf{Length = 28}$

<em>Assume she starts from the origin (0,0)</em>

The midpoint would be:

$\mathbf{Mid = \frac 12 \times Length}$

$\mathbf{Mid = \frac 12 \times 28}$

$\mathbf{Mid = 14}$

So, the vertex of the parabola is:

$\mathbf{Vertex = (Mid,Height)}$

Express properly as:

$\mathbf{(h,k) = (14,20)}$

A point on the graph would be:

$\mathbf{(x,y) = (28,0)}$

The equation of a parabola is calculated using:

$\mathbf{y = a(x - h)^2 + k}$

Substitute $\mathbf{(h,k) = (14,20)}$ in $\mathbf{y = a(x - h)^2 + k}$

$\mathbf{y = a(x - 14)^2 + 20}$

Substitute $\mathbf{(x,y) = (28,0)}$ in $\mathbf{y = a(x - 14)^2 + 20}$

$\mathbf{0 = a(28 - 14)^2 + 20}$

$\mathbf{0 = a(14)^2 + 20}$

Collect like terms

$\mathbf{a(14)^2 =- 20}$

Solve for a

$\mathbf{a =- \frac{20}{14^2}}$

$\mathbf{a =- \frac{20}{196}}$

Simplify

$\mathbf{a =- \frac{5}{49}}$

Substitute $\mathbf{a =- \frac{5}{49}}$ in $\mathbf{y = a(x - 14)^2 + 20}$

$\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}$

Hence, the equation of the parabola that describes the path of her jump is $\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}$

See attachment for the graph

Read more about equations of parabola at:

brainly.com/question/4074088

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3 years ago

Of the relations graphed below, three are functions and one is not.

AlekseyPX

Answer:

Graph B

Step-by-step explanation:

the line is at some point perpendicular to the y-axis, there is no unique y value for this x value, which contradicts the definition of a function.

7 0

3 years ago