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3 years ago

Factor using a GCF: 16xy2+28xy+8y

Mathematics

1 answer:

Lorico [155]3 years ago

7 0

Answer:

4y( 4xy + 7x +2)

Step-by-step explanation:

16xy^2+28xy+8y

16xy^2 =2*2*2*2*x*y*y

28xy = 2*2*7 *x*y

8y = 2*2*2*y

The common factors are 2*2*y = 4y

2*2*2*2*x*y*y + 2*2*7 *x*y+2*2*2*y

2*2*y( 2*2*x*y + 7 *x+2)

4y( 4xy + 7x +2)

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$\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill$

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Factor using a GCF: ​ 16xy2+28xy+8y

Factor using a GCF: 16xy2+28xy+8y