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3 years ago

Happy (Valentine) day!

Mathematics

2 answers:

Kazeer [188]3 years ago

6 0

Answer:

happy Valentine day you too

Anestetic [448]3 years ago

3 0

Happy Valentine's day!!! May God bless you!

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tyler read 15 pages of a book. Ann read 9 pages of the same book. Did Tyler read 4 more pages than Ann? Explain

Slav-nsk [51]

No because fifteen minus nine is six, so Tyler read six more pages than Ann.

5 0

4 years ago

A large on-demand, video streaming company is designing a large-scale survey to determine the mean amount of time corporate exec

Firdavs [7]

Answer:

554 executives should be surveyed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Standard deviation of 3 hours.

This means that $\sigma = 3$

The 95% level of confidence is to be used. How many executives should be surveyed?

n executives should be surveyed, and n is found with $M = 0.25$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.25 = 1.96\frac{3}{\sqrt{n}}$

$0.25\sqrt{n} = 1.96*3$

$\sqrt{n} = \frac{1.96*3}{0.25}$

$(\sqrt{n})^2 = (\frac{1.96*3}{0.25})^2$

$n = 553.2$

Rounding up:

554 executives should be surveyed.

8 0

3 years ago

Jk i know the answer

anygoal [31]

Answer: good for you

Step-by-step explanation:

4 0

3 years ago

For a science project, 3/4 of the students chose to make a poster and 0.25 of the students wrote a report. Rosa said that more s

Viktor [21]

She’s right because .25 converted into a fraction is 1/4 and 3/4 is greater than 1/4

3 0

3 years ago

Please Pleaseee help...will make the brainliest

snow_lady [41]

Answer:

A and F.

Explaination:

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3 years ago

Read 2 more answers