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dsp73
3 years ago
6

the piggybank had 25.65 in dimes and quarters if there were 20 more quarters than dimes, how many dimes were in the piggybank

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0
X = number of dimes
y = number of quarters
---
10x + 25y = 2565
y = x + 20
---
put the system of linear equations into standard form
---
10x + 25y = 2565
x - y = -20
---
copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
---
solution:
x = 59
y = 79
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A rectangular prism has a length of 4 cm and a width of 5 cm.The volume of the prism is 200 cu cm .The height is unknown.Explain
Kaylis [27]

Answer:

Well just gonna explain kn the bottom but the answer is 10

Step-by-step explanation:

what you would have to do first is to jusy do 5x4 which is 20 then since you wanna find the volume yoi qould juat do 200 divide by 20 which is 10

3 0
4 years ago
What is the slope of the line passes through the points (-2,-3) and (5,4)?​
Taya2010 [7]

The slope is 1.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

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5 0
1 year ago
Answer and explanation please?
nignag [31]
The answer would be A. m= -3/5 and b=-4/5
"m= -5-1 divided by 7--3
or, -6/10
or, -3/5.

to find the (B)

<span><span>(-3,1). y=mx+b or 1=-3/5 × -3+b, or solving for b: b=1-(-3/5)(-3). b=-4/5.</span><span>(7,-5). y=mx+b or -5=-3/5 × 7+b, or solving for b: b=-5-(-3/5)(7). b=-4/5.</span></span>See! In both cases we got the same value for b. And this completes our problem.

<span><span>The equation of the line that passes through the points(-3,1) and (7,-5)is</span><span>y=-3/5x-4/5"</span>
Source: webmath</span>
5 0
3 years ago
Could you help me with this question?
Contact [7]

Answer:

C

Step-by-step explanation:

5=x+3

subtract 3 on both sides

5-3=x+3-3

2=x

5 0
3 years ago
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