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nika2105 [10]
3 years ago
15

Solve for x (5x+15)(3x-3)

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0
Well when ever you're doing order of operations you always use please excuse my dear aunt sally please means parentheses ALWAYS GO FIRST Excuse means experience which if there's no parentheses exponents go first to my name is multiplication after parentheses multiplication always go first if there's no parentheses dear means division after multiplication comes division on means addition but pretty much after the multiplication parentheses and the division you complete the rest of the problem using the left to right method now the answer to this problem is
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how do you do this? i don't need it solved i just don't know how to do it. i know the note on the side says how to but i'm still
olchik [2.2K]

Answer:

Perimeter of triangle J= 18.0 units (3 s.f.)

Perimeter of triangle K= 19.0 units (3 s.f.)

Step-by-step explanation:

The length of each side of the triangle can be found using the distance formula below:

\boxed{d=  \sqrt{(y1- y2)^{2} + (x1 - x2)^{2}  } }

Please see the attached pictures for full solution.

5 0
3 years ago
What does 6-2p+5p-3 equal
viva [34]

Answer:

3 + 3p

Step-by-step explanation:

since there's no equal sign or no value that it shows all of that added together is equivalent to it's not really equal to anything. However if you're asking what that equation would look like if you simplified it down , then it would be 3 + 3p because you combine the like terms

4 0
3 years ago
Read 2 more answers
The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p
Juliette [100K]

Check the picture below.


based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,


\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)


\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}


now, we can plug those values on A = (1/2)bh,


\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5

7 0
3 years ago
How to write 8.517 in word form
inysia [295]
<span>Answer:

8.517 in word form is eight and five hundred seventeen thousandths or eight</span>
3 0
3 years ago
Solve for x : ax+v=3(x-c)
never [62]

Answer:

x=\frac{3c+v}{a-3}

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

3 0
3 years ago
Read 2 more answers
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