The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The p
robability that the mean height of an SRS of 10 young women exceeds 66.5 inches is ＿
normalcdf(66.5, 99999999, 64.5, 2.5)
1 - normalcdf(66.5, 99999999, 64.5, 0.7906)
normalcdf(-99999999, 66.5, 64.5, 2.5)
normalcdf(66.5, 99999999, 64.5, 0.7906)
normalcdf(66.5, 99999999, 0, 1)
1 - normalcdf(66.5, 99999999, 64.5, 2.5)
1 - normalcdf(66.5, 99999999, 0, 1)
normalcdf(--99999999, 66.5, 64.5, 0.7906)
plz need help number 1 2 3 4 5 are pic
normalcdf(66.5, 99999999, 64.5, 2.5)
1 - normalcdf(66.5, 99999999, 64.5, 0.7906)
normalcdf(-99999999, 66.5, 64.5, 2.5)
normalcdf(66.5, 99999999, 64.5, 0.7906)
normalcdf(66.5, 99999999, 0, 1)
1 - normalcdf(66.5, 99999999, 64.5, 2.5)
1 - normalcdf(66.5, 99999999, 0, 1)
normalcdf(--99999999, 66.5, 64.5, 0.7906)
plz need help number 1 2 3 4 5 are pic
1 answer:
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Answer:
x = 2
Step-by-step explanation:
The parallel lines divide the transversals into proportional segments, that is
=
( cross- multiply )
9(x + 4) = 54 ( divide both sides by 9 )
x + 4 = 6 ( subtract 4 from both sides )
x = 2