(_/18+2_/3)^(2
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
If someone could pls help me this im new to this and yes tysm if you do :)
1 answer:
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the table below:
Grade In favor Opposed Undecided Total
Grade 9 6 4 8 18
Grade 10 10 11 9 30
Grade 11 12 15 11 38
Grade 12 15 6 14 35
If the principal randomly selects a student in grade 10 from this survey,
the probability that the student is opposed to extending the school day
P ( student in grade 10 is opposed)= Number of student in opposed(grade10) / total number of students in grade 10
Number of student opposed who is in grade10 = 11
total number of students in grade 10 = 30
P( student in grade 10 is opposed)=
= 0.37
the probability that the student is opposed to extending the school day= 0.37