Answer:
Step-by-step explanation:
The letters are easy enough.
y^3 determines that 3 ys are needed. y^2 is taken in by the cubed.
x^4 determines that 4 xs are needed. x^3 is part of x^4 and you don't need any more xs
12 and 42 are the parts that will cause the problem. Factor them both into prime factors
12: 2 * 2 * 3
42: 2 * 3 * 7
You need two 2s.
You need one 3
You need one 7
LCD = 2 *2*3 * 7 = 84
Answer:
the first blank is 10
and the second blank is 5
Step-by-step explanation:
Answer:
1 999 000
Step-by-step explanation:
Formula:
………………………………………
Then
Answer:
a, (x^2)^3 = x^6 = x^2.x^4
b, x^5·x^7 = x^12 = (x^3)^4
c, x^4·x^22 = x^26 = (x^2)^13
d, (x^2)^8 = x^16 = x^2.x^14
e, x^10/x^3 = x^7 = x^20.x^(-13)
f, x^(-3) = x^4.x^(-7)
g, 1/x^(-3) = x^3 = x^4.x^(-1)
Hope this helps!
:)
