I can't type it I have to solve on a paper for you
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Answer:
A. 15
Step-by-step explanation:
To solve this you need to compare the lengths given to you in the question statement.
Because the lines originate from a single point, they're like triangles. We can easily see a triangle AGF and a triangle ADE, right?
Both triangles are similar triangles, so we can see triangle ADE as a larger version of angle AGF.
They give you the dimension of A F and A E (through A F + F E) to establish a ratio... and they give you A G, asking for A D.
So, A F = 16, A E = 20 (16 + 4), A G = 12.
Since A D is to A G what A E is to A F, we can easily make the following cross-multiplication:

So, A D = (A G * A E)/A F
A D = (12 * 20) / 16 = 15
Answer:
Step-by-step explanation:
<u>Given:</u>
Area of the base :
Height of cylinder:
<u>The volume is:</u>
- V = Bh
- V = 50.24*3 = 150.72 ft³
Answer: 10.00
Step-by-step explanation:
You had to multiply and divide and see what you get.