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Pepsi [2]
2 years ago
9

Estimate the quotient. 1,976 ÷ 3 600 50 550 60

Mathematics
2 answers:
Ivan2 years ago
8 0
600 I think this is the answer I tried my best
Radda [10]2 years ago
3 0

Answer:

600 is closest to the actual answer so pick that.

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Line 2x-4y-7=0 meets the x axis at point (k,0). Find the value of k
kolbaska11 [484]
K=4
add seven on both sides
2x-4y=7
add 4y on both sides
2x=7+4y
divide 2 on both sides
x=7+4y/2
plug that into original equation
2(7+4y/2)-4y-7=0
7 and 4y cancel out
2(2)=0
4=0
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How old am I if 1,114 reduced by twice my age is 400?
Natasha_Volkova [10]

Answer:

13

Step-by-step explanation:

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Lelu [443]
1/2 gallon of milk makes 10 glasses.
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A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
2 years ago
Does the equation y = x represent a function? Explain why or why not.
Sphinxa [80]

Answer:

It represents a function because it consists of x-intercept and y-intercept hence can be plotted.

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2 years ago
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