The probability of getting heads on the first toss is 1/2 .
Then, the probability of getting heads on the second toss is 1/2 .
Then, the probability of getting heads on the third toss is 1/2 .
The probability of all three things happening is ...
(1/2) x (1/2) x (1/2) = 1/8 = 0.125 = 12.5% .
Answer:
p=0.25
Step-by-step explanation:
Given that a club can select one member to attend a conference. All of the club officers want to attend. There are a total of four officers, and their designated positions within the club are President (P), Vice dash President (Upper V )comma Secretary (Upper S )comma nbspand Treasurer (Upper T ).
Sample space would be
a){ {P}, {V}, {S} {T}} is the sample space with notations standing for as given in the question
b) Each sample is equally likely. Hence we have equal chances for selecting any one out of the four.
If probability of selecting a particular sample of size I is p, the by total probability axiom we have
\begin{gathered}4p =1\\p =0.25\end{gathered}
4p=1
The answer is 5.35, 275, 336, and 535
Answer: 2.25 = 18.90
Step-by-step explanation: Hope This Helps
yes yes i agree completely thats the snswet answer* 25 a b c d 46:77 77/55
