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2 years ago

Round 0.71 to the nearest tenth. 0.5 0.7 0.75 0.8

Mathematics

2 answers:

tigry1 [53]2 years ago

6 0

0.7 it is rounded to the nearest tenth

rjkz [21]2 years ago

4 0

Answer:

0.7

Step-by-step explanation:

This one is simply pretty easy. the 7 in this is in the tenths place, and the 1 in this is in the hundredths place

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A suitable probability app shows the 1st percentile to be at about 11040 pages.

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The app shown has an error in the first decimal digit. The number is closer to 11040.82301. We expect the manufacturer would round to the nearest 10 or 50 or 100 in advertising.

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3 years ago

Use whichever method you choose to solve the system of equations: x + y = 6 and 3x + 5y = 26

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X+y=6 , 3x+5y=26 here is your answer:)

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2 years ago

Calculate the perimeter of the composite figure. Round your answer to the nearest hundredth. Use 3.14 for $\pi$ .

Elena-2011 [213]

1. Perimeter is 3 + 3 +3 +4 +5 = 18 feet

Area = 3*3 = 9, 1/2*3*4 = 6, 9 + 6 =15 square feet

2. perimeter = 2.5 +2.5+ 2.5+2.5+0.5+0.5 = 11 meters

Area = 3*.5 = 1.5, 3*2=6, 6+1.5 = 7.5 square meters

3. perimeter = 3.14*2*3 = 18.84 +8 = 26.8 inches

Area = 6*4 = 24 + 3.14*3^2 = 28.26 = 28.26 +24 = 52.3 inches

4. surface area = 2*π*6*20+2*π*6^2= 980.2 yards

Volume = π*6^2*20 = 2261.9 cubic yards

5.surface area = 2*(9*7+2*2+2*9) = 190 cm

Volume = 2*7*9 = 126 cubic cm

6. surface area = 2*(11*11+11*11+11*11) = 726 mm

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2 years ago

A track and field playing area is in the shape of a rectangle with semicircles at each end . The perimeter of the track is to be

MAVERICK [17]

We can let the radius of the semi circles be r and x can be the length of the rectangle.
The perimeter will be Perimeter = 2x + 2pr = 1200
The area of the rectangle is Area = x(2r)
Once we solve the perimeter equation, you get x = 600.
Put this into the area equation and you get Area = (600 - pr)(2r)
The maximum then gives r = 95. 493 and area 57, 295.8
Dimensions

Height is twice the radius or 190.986. Find base use equation x = 600 - p(95.493) = 300.

This means dimensions are 300 by 190.986

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3 years ago

Suppose that for a recent admissions class, an Ivy League college received 2,851 applications for early admission. Of this group

masya89 [10]

Answer:

a. P(E) = 1033/ 2851=0.3623

P(R) = 854/2851=0.2995

P(D) = 964/2851=0.3381

P(E ∩ D) = P(E) +P(D)= 0.3623 +0.3381= 0.7004

(d) 0.423 158

Step-by-step explanation:

a. P(E) = 1033/ 2851=0.3623

P(R) = 854/2851=0.2995

P(D) = 964/2851=0.3381

(b) Are events E and D mutually exclusive?

Yes these events are mutually exclusive. If students are deferred they may be admitted later but not early. Mutually Exclusive or disjoint events do not occur at the same time.

P(E ∩ D) = P(E) +P(D)= 0.3623 +0.3381= 0.7004

(c) For the 2,375 students who were admitted, the probability that a randomly selected student was accepted during early admission is

P(E) = 1033/ 2851=0.3623

P(E) + P(D for later admission) =0.3623 + 18%*0.3381

=0.3623 + 0.0609 = 0.423 158

3 0

3 years ago