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2 years ago

Domain and range of a function in an entire graph

Mathematics

1 answer:

RideAnS [48]2 years ago

4 0

Answer:

Definition of the domain and range

The domain is all x-values or inputs of a function and the range is all y-values or outputs of a function. When looking at a graph, the domain is all the values of the graph from left to right. The range is all the values of the graph from down to up.

Step-by-step explanation:

I hope this can h help you

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The three angles of a triangle are in the ratio 5:4:1. Find all the angles of the triangle.

solniwko [45]

Answer:

Step-by-step explanation:

let the first angle be 5x

second be 4x

and third be 1x

as we know that by adding all the sides of triangle we get 180°

therefore ,

5x+4x+1x=180°

10x=180°

hence ,

x=18°

first angle - 18*5 = 90°

second angle - 18*4=72°

third angle - 18°

HOPE THIS HELPS YOU !!!

6 0

3 years ago

Read 2 more answers

ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?

MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = $\sqrt{(x_2-x_1)^2 +( y_2-y_1)^2$

Step 1: Finding the length of EF

By using distance formula,

$EF = \sqrt{(-7 - 0)^2 + (4-0)^2}$

$EF = \sqrt{(49) + (16)}$

$EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\$

Step 2: Finding the length of FG

By using distance formula,

$FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}$

Step 2: Finding the length of GE

$GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8$

Thus we could see that the sides EF = FG

So it is a isosceles triangle.

6 0

3 years ago

My questions are in the picture please help

Marrrta [24]

21.

So to solve for the value of a variable in an equation, you would need to isolate x on one side. The first thing you have to do is multiply 2 and (x + 7) together, which can be rewritten as 2(x) + 2(7). After multiplying, your equation would be: $2x+14+3x=12$ , or A.

22.

So the rule with multiplying exponents with the same base is to add the exponents together, and the rule with dividing exponents with the same base is to subtract the exponents. Your equation will be simplified as such:

$4^{(3+4)-9}\\ 4^{7-9}\\ 4^{-2}$

Now the rule with converting negative exponents into fractions is $x^{-m}=\frac{1}{x^m}$ . In this case, 4^-2 would turn into $\frac{1}{4^2}$ , or C, which is your final answer.