Question

A cyclist rides his bike at a speed of 18 miles per hour. What is this speed in feet per second? How many feet will the cyclist travel in 20 seconds? In your computations, use the fact that 1 mile is equal to 5280 feet.

Answer 1

Answer:

The distance travel by cyclist in 20 seconds is 528 feet .

Step-by-step explanation:

Given as :

The speed of cyclist riding bike = s = 18 miles per hour

Let The distance cover by cyclist in 20 seconds = d feet per sec

Now, According to question

∵ 1 miles = 5280 feet

∴ 18 miles = 5280 × 18 = 95,040 feet

So, The speed of cyclist in feet per hour = 95,040 feet per hour

Again,

∵ 1 hours = 3600 seconds

So, The speed of cyclist in feet per sec = $\dfrac{95040}{3600}$ ft/sec

∴ The speed of cyclist in feet per sec = 26.4 feet per second

Again

∵ In 1 sec the distance cover by cyclist = 26.4 feet

∴  In 20 sec the distance cover by cyclist = 26.4 × 20 feet

i.e In 20 sec the distance cover by cyclist = 528 feet

Hence, The distance travel by cyclist in 20 seconds is 528 feet . Answer