170 is the answer to the question
I’m sorry, need more information
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
Okay I can help you with your math!!
Answer:
Opposite Angles Theorem
Step-by-step explanation:
All opposite angles are congruent, meaning that two angles created by intersecting lines that oppose eachother are equal in size. The theorem goes by different names, so I don't know exactly what your teacher is asking for, but I hope I could help.
