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2 years ago

Solve 5p(2p - 3)(p + 7) = 0. p=_, p=, p=___

Mathematics

1 answer:

Luba_88 [7]2 years ago

5 0

Answer:

5p(2p-3)(p+7)=0

10p-15 p +7 =0

10p+p=0+15-7

11p =8

11p=8

p=8/11

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Using a simulator at space camp, you practice landing your individual spaceship on landing platforms that have different shapes

Mila [183]

The Area of the platform is 33m²

Step-by-step explanation:

As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m

Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m

Since the platform is five-sided, the figure can be broken down into constituting parts

Parallelogram ║ABCE
Δ DCE

Are of the figure= Area of ║ABCE+ area Δ DCE

Area of ║ABCE= breadth * height

= 6*4 ⇒24m ²

Area Δ DCE= ½*(base)(height)

Putting the value of base is 6m and height as 3m

Area Δ DCE= ½*6*3

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Total area= 24+9= 33m ²

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3 years ago

If x = 14, which equation is true?

lozanna [386]

Answer:

The answer should be C.

2(14 - 3) = 22

2(11) = 22

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3 years ago

I need to divide and then write in simplest form 2/5÷1/6

My name is Ann [436]

Answer:

2/5÷1/6 = 2/1

Step-by-step explanation:

2/5÷1/6 = 2/5 times 6/1 = 12/5, 12÷2 is 6, 5 ÷ 5 is 1, so it's 2/1.

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3 years ago

PART A: Mrs. konsdorf claims that angle R is a right angle.Is Mrs. konsdorf correct? explain your reasoning PART B: if T is trab

Anna007 [38]

Answer:

Part A: Angle R is not a right angle.

Part B; Angle GRT' is a right angle.

Step-by-step explanation:

Part A:

From the given figure it is noticed that the vertices of the triangle are G(-6,5), R(-3,1) and T(2,6).

Slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

The product of slopes of two perpendicular lines is -1.

Slope of GR is

$\text{Slope of GR}=\frac{1-5}{-3-(-6)}=\frac{-4}{3}$

Slope of RT is

$\text{Slope of RT}=\frac{6-1}{2-(-3)}=\frac{5}{5}=1$

Product of slopes of GR and RT is

$\frac{-4}{3}\times 1=\frac{-4}{3}\neq -1$

Therefore lines GR and RT are not perpendicular to each other and angle R is not a right angle.

Part B:

If vertex T translated by rule

$(x,y)\rightarrow(x-1,y-2)$

Then the coordinates of T' are

$(2,6)\rightarrow(2-1,6-2)$

$(2,6)\rightarrow(1,4)$

Slope of RT' is

$\text{Slope of RT'}=\frac{4-1}{1-(-3)}=\frac{3}{4}$

Product of slopes of GR and RT' is

$\frac{-4}{3}\times \frac{3}{4}=-1$

Since the product of slopes is -1, therefore the lines GR and RT' are perpendicular to each other and angle GRT' is a right angle.

6 0

3 years ago

0.2 Times 10^6 in scientific notatation

Ronch [10]

You could move the decimal to the right 6 times
0.2 x 10^6
0200000 or 200,000(remember that if there's only two digits there will be one less zero than the exponent)

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3 years ago

Solve 5p(2p - 3)(p + 7) = 0. p=___, p=____, p=_____

Solve 5p(2p - 3)(p + 7) = 0. p=_, p=, p=___