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inysia [295]
3 years ago
12

What is the slope of the line? 2x - 5y = 9 Choose 1 answers 5 2 O

Mathematics
1 answer:
Zepler [3.9K]3 years ago
5 0

9514 1404 393

Answer:

  D.  2/5

Step-by-step explanation:

The slope is the x-coefficient when the equation is solved for y.

  2x -5y = 9 . . . . . . . given

  -5y = -2x +9 . . . . . .subtract 2x

  y = (-2/-5)x +9/(-5) . . . . divide by -5

  y = 2/5x -9/5

The coefficient of x is 2/5. That is the slope of the line.

The slope is 2/5.

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Tanzania [10]

Answer:

Step-by-step explanation:

8 0
4 years ago
What are the values of x and y?
ss7ja [257]

Answer: x=35 and y=72.5

Step-by-step explanation:

Everything os 360, so x is 35 because it los like it has the same measure as the another 35, so if you substract 70 360=290 and 290/4 = 72.5

5 0
3 years ago
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
In circle L, points E and F lie on the circle such that E, F and L are not collinear. If LE, LF and EF are drawn then which of t
frozen [14]

Answer:

<u>option (2) it is and isosceles triangle. </u>

Step-by-step explanation:

In circle L, points E and F lie on the circle such that E, F and L are not collinear

If LE, LF and EF are drawn

So, LE = EF = the radius of the circle L

So, LEF is an isosceles triangle.

The answer is option (2) it is and isosceles triangle.

8 0
3 years ago
2 / 5 + ? / 15 = 16 / 15
maksim [4K]

Answer:

65

Step-by-step explanation:

I dont know the answer hope this helps

8 0
3 years ago
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