Question

A

Answer 1

Answer:

Step-by-step explanation:

$(3n+2)^{2} = (3n+2)(3n+2)$

$9n^{2} +12n+4$ - I expanded the above brackets

$9n^{2} +12n+3+1$  - I separated the 1 from 4 to make 3+1

$3(3n^{2} +4n+1)+1$ - I took out a factor of 3

= 1 more than a multiple of 3