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stiv31 [10]
3 years ago
7

Whats the best expansion for (x+5a+5b)(x+a-b) ​

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

x² + 6ax + 4bx + 5a² - 5b²

Step-by-step explanation:

(x+5a+5b )(x+a-b) ​

x² +a x -bx +5ax + 5a² -5ab + 5bx + 5ab -5b²

x² + 6ax + 4bx + 5a² - 5b²

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12 feet or 4 feet.......

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the diameter of a gigantic Ferris wheel is 185 meters. if a man rides a ferris wheel for one revolution find how far he travels
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Step-by-step explanation:

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3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
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IRINA_888 [86]

Answer:

X is intercepted at -7

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Step-by-step explanation:

5 0
3 years ago
Nicole is cooking pancakes. The recipe calls for 4 1/3 cups of milk. She accidentally put in 4 3/4 cups . How many extra cups di
Ugo [173]

4 3/4 - 4 1/3

= 4 9/12 - 4 4/12

= 5/12 <==== extra cup put in

3 0
3 years ago
Read 2 more answers
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