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saveliy_v [14]
3 years ago
14

What is the midpoint of a segment with These endpoints (-6,-9) and (16,5)

Mathematics
1 answer:
lora16 [44]3 years ago
7 0

~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 16 -6}{2}~~~ ,~~~ \cfrac{ 5 -9}{2} \right)\implies \left( \cfrac{10}{2}~~,~~\cfrac{-4}{2} \right)\implies (5~~,~-2)

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Y+x=14 and y-5x=2 <br><br> It has to be graphed
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Y is 12. X is 2 and if you add 12 plus 2 it makes 14. and 12 minus 5 times 2 equals 2

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A cone is stacked on top of a cylinder. They both share a circular base. The total height of the composite figure is 25. The hei
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Answer:

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Step-by-step explanation:

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A TV show, Lindsay and Tobias, recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to that show. A
kati45 [8]

Answer:

8.6% probability that none of the households are tuned to Lindsay and Tobias.

There is a 91.4% probability that at least one household is tuned to Lindsay and Tobias.

There is a 32.2% probability that at most one household is tuned to Lindsay and Tobias.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are watching the TV show, or they are not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 11, p = 0.20

Find the probability that none of the households are tuned to Lindsay and Tobias.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.20)^{0}.(0.80)^{11} = 0.086

8.6% probability that none of the households are tuned to Lindsay and Tobias.

Find the probability that at least one household is tuned to Lindsay and Tobias.

Either no household is tuned, or at least one is tuned. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.086 = 0.914

There is a 91.4% probability that at least one household is tuned to Lindsay and Tobias.

Find the probability that at most one household is tuned to Lindsay and Tobias.

This is

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = 1) = C_{11,1}.(0.20)^{1}.(0.80)^{10} = 0.236

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.086 + 0.236 = 0.322

There is a 32.2% probability that at most one household is tuned to Lindsay and Tobias.

8 0
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HELPP pleez
SpyIntel [72]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Select the correct answer.
mixer [17]

The solution to the inequality 6x + 3y ≤ 84 is the dark region shown and the point (9, 10) satisfies this inequality.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the number of rides Darren can ride and y represent the number of exhibits he can view. Hence:

6x + 3y ≤ 84

The solution to the inequality 6x + 3y ≤ 84 is the dark region shown and the point (9, 10) satisfies this inequality.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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