The answer is -3 . Use the gradient formula y2-y1/x2-x1
Answer:
x=15, y=12
Step-by-step explanation:
Please see the attached pictures for full solution.
The solution to the given expression negative four and one third ÷ two and one fifth is -1 32/33
<h3>Fraction division</h3>
negative four and one third ÷ two and one fifth
-4 1/3 ÷ 2 1/5
= -13/3 ÷ 11/5
- Multiply by the reciprocal of 11/5
- The reciprocal of 11/5 is 5/11
= -13/3 × 5/11
= (-13 × 5) / (3 × 11)
= -65 / 33
= -1 32/33
Therefore, the solution to the fraction is -1 32/33
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Answer:
Step-by-step explanation:
Product of slope of perpendicular lines = -1
6x + 5y = 30
Write this equation in y = mx + b form
5y = -6x + 30
y = 

Slope of this line m₁ = -6/5
m₁ * m₂ = -1
m₂ = -1÷m₁ = -1 *
& (-6 , -7)
Equation of the required line: y - y₁ = m (x - x₁)
![y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2](https://tex.z-dn.net/?f=y%20-%20%28-7%29%20%3D%20%5Cfrac%7B5%7D%7B6%7D%28x%20-%20%5B-6%5D%29%5C%5C%5C%5Cy%20%2B%207%20%3D%20%5Cfrac%7B5%7D%7B6%7Dx%20%2B%206%20%2A%5Cfrac%7B5%7D%7B6%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B5%7D%7B6%7Dx%20%2B5-7%5C%5C%5C%5Cy%3D%5Cfrac%7B5%7D%7B6%7Dx-2)