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3 years ago

Which of the following are factors of 6x^2+30x-36?

Mathematics

2 answers:

Neko [114]3 years ago

5 0

The factor is x-6 since the two factors of your equation are (6x-6) and (x-6)

iogann1982 [59]3 years ago

4 0

6x^2+30x-36
(6x-6)(x+6)

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X - 8 = -12<br><br> Solve for x<br><br> x = ?

Cerrena [4.2K]

$\\ \sf\longmapsto x-8=-12$

$\\ \sf\longmapsto x=-12+8$

$\\ \sf\longmapsto x=-4$

Done

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2 years ago

Read 2 more answers

What's the step by step progress for writing 14.35 in scientific notation

Dmitry [639]

For scientific notation, you always want 1 digits in front of the decimal.

Ex) 7.39*10^5

Move the decimal point in between the 1 and 4, or 1 place to the left.

1.435

Since the decimal point was moved 1 place to the left, the exponent after 10 will be 1.

1.435*10^1

1.435*10^1 is your final answer.

1.435*10 is the same thing also.

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3 years ago

Find the measure of the angle marked with the question mark.

mel-nik [20]

Answer:

52 degrees

Step-by-step explanation:

The 38 degree angle and the angle marked with a question mark are complimentary, which means they add up to 90 degrees. Knowing this, subtract 38 from 90 to find the mystery angle.

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2 years ago

5xy + 4yz + 3zx for x = -1, y =-3, z = 4

neonofarm [45]

Answer:

-45

Step-by-step explanation:

5 *-1 *-3= 15

4 *-3 *4= -48

3 *4 *-1=-12

15 -48 -12= -45

8 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

3 years ago