He used an incorrect time ratio converting hours to minutes.
The given inequality is:

This inequality can be divided in two parts as:
a)

b)

Solving part a:

Solving part b:

Therefore, the solution to the given inequality is

and

. Combining both the ranges we get the solution:

.
In interval notation, this solution can be expressed as [1,5]
Answer:
-18
Step-by-step explanation:
5a2-7-b3


Therefore, -18 is your answer.
Hope this helped! :)
0.5 < x < 16.5 given: Two sides of triangle: 8.0 units and 8.5 units
Measure of third side = x
According to the triangle's inequality,
Sum of any two sides > third side. (i)
Difference between the sides < third side. (ii)
If x is the third side, then
x < 8+8.5 [Using (i)]
i.e. x< 16.5
Also, x > 8.5-8 [Using (ii)]
i.e. x> 0.5
Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.
Answer:
(4, -1)
Step-by-step explanation:
(4, y) is a solution to x - 2y = 6.
Find the value of y:

The value of y is '-1'.
(4, -1) is a solution to the equation.
Hope this helps.