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Feliz [49]
3 years ago
14

Which of the following represents the set of possible rational roots for the polynomial shown below 2x^3+5x^2-8x-20=0

Mathematics
2 answers:
kvasek [131]3 years ago
8 0

Answer:

± 1/2,±1, ±2,± 5/2, ±4 ,±5 , ±10, ± 20

Step-by-step explanation:

We can use the rational root theorem to find all the possible roots

2x^3+5x^2-8x-20=0  

Let the constant term  be called p and the leading term be called q.  Then the possible roots are the positive and negative roots of the factors of p/q

p = 20

q = 2

Factors of p: 1,2,4,5,10,20

Factors of q: 1,2

Possible roots

    1 ,2,4,5,10,20

±   --------------------------------------------------------

      1,2

So we get

±1, ±2, ±4 ,±5 , ±10 ± 20 ± 1/2± 2/2,±4/2,± 5/2,± 10/2,± 20/2

Simplifying

±1, ±2, ±4 ,±5 , ±10, ± 20, ± 1/2,± 1,±2,± 5/2,± 5,± 10

Eliminating repeats

±1, ±2, ±4 ,±5 , ±10, ± 20 ,± 1/2,± 5/2

Putting them in numerical order

± 1/2,±1, ±2,± 5/2, ±4 ,±5 , ±10, ± 20

Masteriza [31]3 years ago
3 0

Answer:

Its Option 1

Step-by-step explanation:

The possible rational roots will have a numerator that divides 20 (the last number) and a denominator that divides 2 (the coefficient of x^3).

For example 20/2, 10/2 and -1/2  =  10, 5 and -1/2.

The correct answer is the first option.

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35% is 7 out of what number?
o-na [289]

Answer:

The number is <u>20</u>.

Step-by-step explanation:

In this question, it is said that 35% of a number is equal to 7, then what is that number?

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Now, according to the question :

\begin{gathered} \begin{array}{l} \quad{\dashrightarrow{\sf{35 \% \: of \: x = 7}}}\\\\\quad{\dashrightarrow{\sf{\dfrac{35}{100} \: of \: x = 7}}}\\\\\quad{\dashrightarrow{\sf{\dfrac{35}{100}  \times x = 7}}}\\\\\quad{\dashrightarrow{\sf{\dfrac{35 \times x}{100} = 7}}}\\\\\quad{\dashrightarrow{\sf{\dfrac{35x}{100} = 7}}}\\\\\quad{\dashrightarrow{\sf{x = 7 \times \dfrac{100}{35}}}}\\\\\quad{\dashrightarrow{\sf{x =\dfrac{700}{35}}}}\\\\ \quad{\dashrightarrow{\sf{x = \cancel{\dfrac{700}{35}}}}}\\\\ \quad{\dashrightarrow{\sf{x =20}}}\\\\ \quad{\star{\underline{\boxed{\tt{\red{x =20}}}}}} \end{array}\end{gathered}

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\rule{300}{2.5}

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Answer:

The probability is  P( X \le 4 ) = 0.0054

Step-by-step explanation:

From the question we are told that

   The percentage that are on time is  p =  0.76

   The  sample size is n =  11

   

Generally the percentage that are not on time is

     q =  1- p

     q =  1-  0.76

     q = 0.24

The  probability that no more than 4 of them were on time is mathematically represented as

        P( X \le 4 ) =  P(1 ) +  P(2) + P(3) +  P(4)

=>     P( X \le 4 ) =  \left n } \atop {}} \right.C_1 p^{1}  q^{n- 1} +   \left n } \atop {}} \right.C_2p^{2}  q^{n- 2} +  \left n } \atop {}} \right.C_3 p^{3}  q^{n- 3}  +  \left n } \atop {}} \right.C_4 p^{4}  q^{n- 4}

P( X \le 4 ) =  \left 11 } \atop {}} \right.C_1 p^{1}  q^{11- 1} +   \left 11 } \atop {}} \right.C_2p^{2}  q^{11- 2} +  \left 11 } \atop {}} \right.C_3 p^{3}  q^{11- 3}  +  \left 11 } \atop {}} \right.C_4 p^{4}  q^{11- 4}

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= \frac{11! }{ 10! 1!}  (0.76)^{1}  (0.24)^{10} +   \frac{11!}{9! 2!}  (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!}  (0.76)^{3}  (0.24)^{8}  + \frac{11!}{7!4!}  (0.76)^{4}  (0.24)^{7}

P( X \le 4 ) = 0.0054

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