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2 years ago

What is the area of a rectangle if one side has a length of 12x^3 and

Mathematics

1 answer:

mojhsa [17]2 years ago

3 0

Answer:

The area of this rectangle is 72x^5

Step-by-step explanation:

A = l ∙ w

Let, l = length

Let, w = width

Step 1: Substitute the length and width for the two given values

1. A = (12x³)(6x²)

Step 2: Multiply

1. A = 72x^5

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PLEASE HELP ASAP, I WILL GIVE BRAINLESSLY ANSWER <br> SHOW WORK PLEASE

zhannawk [14.2K]

Answer:

C. $N(t)=150\cdot 3^t$

Step-by-step explanation:

You are given the exponential function $n(t)=ab^t.$

From the table, $N(t)=150$ at $t=0,$ thus

$N(0)=a\cdot b^0\\ \\150=a\cdot 1\ [\text{ because }b^0=1]$

Also $N(t)=450$ at $t=1,$ thus

$N(1)=a\cdot b^1=a\cdot b.$

Since $a=150,$ substitute it into the second equation

$450=150\cdot b\\ \\b=\dfrac{450}{150}\\ \\b=3$

and the expression for the exponential function is

$N(t)=150\cdot 3^t$

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3 years ago

(-38)÷ ------- =not defined.fill in the blanks<br>please fill the answer

Damm [24]

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▹ Answer

▹ Step-by-Step Explanation

The answer is ∞ because anything divided by infinity is not defined.

Hope this helps!

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3 years ago

Find f(-9) for f(x)= -3x^2-20

lions [1.4K]

Answer:

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Step-by-step explanation:

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2 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

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3 years ago

Find the simple interest on $900 for 18 months at a rate of 9.5% per year

Anestetic [448]

To get the simple interest, we must use the formula: I= (p)(r )( t)
So, in this one we need to multiply $900x18x9.% and the answer will be $128.25. This is the amount of interest they are going to pay per year.

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3 years ago