All categories

3 years ago

In quadrilateral ABCD, diagonals AC And BD bisect one another

Mathematics

2 answers:

Ymorist [56]3 years ago

8 0

Segment AP is congruent to segment CP. Segment BP is congruent to segment AP Sides AB and BC are congruent. Triangles BCP and CDP are congruent.

zloy xaker [14]3 years ago

3 0

Segmaent ap Segment

Ap

You might be interested in

Convert into slope-intercept form: <img src="https://tex.z-dn.net/?f=y-1%3Dm%28x-3%29" id="TexFormula1" title="y-1=m(x-3)" alt="

aliina [53]

Answer:

y=2x-5

Step-by-step explanation:

First simplify: y-1=2x-6

y-1=2(x-3)

First simplify and distribute everything.

y-1=2x-6

So, x equals 2 because it got distributed into the numbers inside the parenthesis. Same with the 2 and -3. They multiplied to become -6.

Since it's y-1=2x-6, you can simplify it even more so the -1 goes to the other side and turns into positive 1.

y - 1 (+ 1) = 2x -6 (+ 1)

-1(+1)=0 which leaves just the variable y on the left side.

-6(+1)=-5 which leaves 2x-5 on the right side.

This results in y=2x-5. Hope this helped ;)

6 0

2 years ago

Read 2 more answers

How do you write 77/20 in a decimal

Sveta_85 [38]

Writing it as a decimal would be 3.85 you just divide it

7 0

3 years ago

Read 2 more answers

1/2÷5= to a improper fraction

Leokris [45]

1/10
hope this helps u out!

5 0

2 years ago

Difference quotient for f (x) = 2x + 3 /5x

solniwko [45]

Answer:

1 and -0.6

Step-by-step explanation:

5 0

2 years ago

The area of a circle is 161 in. What is the radius?

kirill [66]

Answer:

Approximately 7.16 in

Step-by-step explanation:

Hi there!

Area of a circle equation: $A=\pi r^2$ where r is the radius

Plug in the given area 161 in.²

$161=\pi r^2$

Divide both sides by π to isolate r²

$\frac{161}{\pi} =\frac{\pi r^2}{\pi} \\\frac{161}{\pi} =r^2$

Take the square root of both sides to isolate r

$=r^2\\\sqrt{\frac{161}{\pi}} =r\\7.16=r$

Therefore, the radius of the circle is approximately 7.16 in.

I hope this helps!

7 0

3 years ago