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2 years ago

In quadrilateral ABCD, diagonals AC And BD bisect one another

Mathematics

2 answers:

Ymorist [56]2 years ago

8 0

Segment AP is congruent to segment CP. Segment BP is congruent to segment AP Sides AB and BC are congruent. Triangles BCP and CDP are congruent.

zloy xaker [14]2 years ago

3 0

Segmaent ap Segment

Ap

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What is the coefficient of the fifth term in (a + b)^9 ?

Margaret [11]

remember a coefficient is the number in front of the variable

the coefficient in the fifth term is 9 since 9 is a number.

8 0

2 years ago

Read 2 more answers

20 points :D

zepelin [54]

Answer:

Step-by-step explanation:

A(1,13), B(5,8)

Let C be 7 units to the right of B: C(5+7,8) = C(12,8)

Let D be 7 units to the right of A: A(1+7,13) = A(8,13)

8 0

2 years ago

The function f(x) = (x – 3)^3 is transformed to

Viktor [21]

Answer:

I DO NOT KNOW BECAUSE I JUST NEED POINTS SORRY

Step-by-step explanation:

SORRY

4 0

2 years ago

A random sample of elementary school children in New York state is to be selected to estimate the proportion p who have received

Anastaziya [24]

Answer:

The minimum sample size required is 461.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

An interval estimate of the proportion p with a margin of error of 0.06. What is the minimum sample size required?

The minimum sample size required is n, which is found when M = 0.06.

We don't have an estimate for the true proportion, which means that we use $\pi = 0.5$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.06 = 2.575\sqrt{\frac{0.5*0.5}{n}}$

$0.06\sqrt{n} = 2.575*0.5$

$\sqrt{n} = \frac{2.575*0.5}{0.06}$

$(\sqrt{n})^2 = (\frac{2.575*0.5}{0.06})^2$

$n = 460.5$

Rounding up

The minimum sample size required is 461.

3 0

2 years ago

Find x. Round your answer to the nearest integer.

vivado [14]

Answer:

B. 20

Step-by-step explanation:

Cos a = b/c

Cos 53° = b/25

b = 25 × 0,6 = 15

x = √(25² - 15²)

x = √(625 - 225)

x = √400

x = 20

6 0

1 year ago