Try this solution (see the attachment, it is consists of 3 steps).
Answer:
X=1
Step-by-step explanation:
The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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Answer:
3
Step-by-step explanation:
the rate of change of the function, or the slope is 3 because to get to one point from the other point in the line, you would have to go up 3 and over 1 (3/1) or just 3.
Hope this helps
Given
Area of the regular pentagon is 6.9 cm².
Find out the perimeter of a regular pentagon
To proof
Formula
Area of regular pentagon is
As given in the question
area of regular pentagon = 6.9 cm²
now equating the area value with the area formula.
Now put
√5 = 2.24 ( approx)
put in the above equation
thus
a² = 4.01
a = √ 4.01
a = 2.0 cm ( approx)
As perimeter represented the sum of all sides.
i.e regular pentagon have five sides of equal length.
Thus
perimeter of the regular pentagon = 5 × side length
= 5 ×2.00
therefore the perimeter of the regular pentagon = 10cm
option c is correct
Hence proved
