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Elza [17]
3 years ago
8

9 — 3x = у 3х – у = -2

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

This could be wrong, but i still wanted to help you.

Step-by-step explanation:

9-3x=y

+9      +9

3x=y

÷3   ÷3

x=y/3

Im sorry if this is wrong

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Arun took a taxi from his house to the airport. The taxi company charged a pick-up fee of $4 plus $4.25 per mile. The total fare
Natasha2012 [34]

Here we must write and solve a linear equation to find the number of miles that Arun traveled in the taxi. We will find that Eva traveled 11 miles.

So we know that the taxi charges a fee of $4.10 and then a plus of $0.50 per mile.

So if you travel for m miles, the cost equation is:

C(m) = $4.10 + $0.50*m

Now, we know that for Eva the total fare (total cost) was $9.60, then we need to solve:

$9.60 = C(m) = $4.10 + $0.50*m

$9.60 = $4.10 + $0.50*m

$9.60 - $4.10 = $0.50*m

$5.50 = $0.50*m

$5.50/$0.50 = m = 11

This means that Arun traveled 11 miles in the taxi.

5 0
2 years ago
Solve x2 + 14x = −24 by completing the square.<br><br> What is the solution set of the equation?
yan [13]
Hope this helps with the question :)

3 0
3 years ago
Read 2 more answers
Ella and jade both ran a marathone ella finished 4 hours 6 mins and 13 seconds jade finished in 4 hours and 3 mins and 18 second
spin [16.1K]

Answer:

Jade is faster than Ella by 2 minutes and 55 seconds.

Step-by-step explanation:

We are told that Ella and Jade both ran a marathon. Ella finished marathon in 4 hours 6 mins and 13 seconds. Jade finished marathon in 4 hours and 3 mins and 18 seconds.

We can write 4 hour 6 minutes 13 seconds as 4 hour 5 minutes 73 seconds. 1 minute has been borrowed to the seconds side, and seconds become 13+60 = 73 seconds.

We can see that Ella took more time than Jade. Let us find how much more time Ella took than Jade by subtracting time taken by Jade from time taken by Ella.  

4\text{ hr }5\text{ min }73\text{ sec }-4\text{ hr }3\text{ min }18{ sec }= 2\text{ min }55\text{ sec }  

We can see that Jade took 2 minute and 55 seconds less than Ella , therefore, Jade was faster than Ella by 2 minutes 55 seconds.

4 0
3 years ago
Cos s=-2/5 and sin t=4/5, s and t are in quadrant II<br> find cos(s+t) and cos(s-t)
mojhsa [17]

Answer:

•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25

•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25

cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗

sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5

5 0
2 years ago
I need help with all please!!
Olenka [21]

Answer:

1. D

2.C

3. A

4.B

5.C

6. C? or D(i think c cause it's 3 places but it can be d because the 0 is just a placeholder)

7.C

8.C

Step-by-step explanation:

3 0
3 years ago
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