Question

Please help due in 20 minutes

Answer 1

• <PTQ=90

In ∆PTQ

Apply Pythagorean theorem

$\\ \tt\hookrightarrow PT^2=PQ^2+QT^2$

$\\ \tt\hookrightarrow PT^2=15.4^2+9.3^2=323.16$

$\\ \tt\hookrightarrow PT=17.9$

In ∆TRQ

$\\ \tt\hookrightarrow tan44.4=\dfrac{QT}{TR}=\dfrac{9.3}{TR}$

$\\ \tt\hookrightarrow 0.9=\dfrac{9.3}{TR}$

$\\ \tt\hookrightarrow TR=\dfrac{9.3}{0.9}=10.3$

• PR=PT+TR=10.3+17.9=28.2cm

Now

Area:-

$\\ \tt\hookrightarrow 1/2bh$

$\\ \tt\hookrightarrow 1/2(28.2)(9.3)$

$\\ \tt\hookrightarrow 14.1(9.3)$

$\\ \tt\hookrightarrow 131.13cm^2$