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Brut [27]
2 years ago
7

Please help due in 20 minutes

Mathematics
1 answer:
MissTica2 years ago
7 0
  • <PTQ=90

In ∆PTQ

Apply Pythagorean theorem

\\ \tt\hookrightarrow PT^2=PQ^2+QT^2

\\ \tt\hookrightarrow PT^2=15.4^2+9.3^2=323.16

\\ \tt\hookrightarrow PT=17.9

In ∆TRQ

\\ \tt\hookrightarrow tan44.4=\dfrac{QT}{TR}=\dfrac{9.3}{TR}

\\ \tt\hookrightarrow 0.9=\dfrac{9.3}{TR}

\\ \tt\hookrightarrow TR=\dfrac{9.3}{0.9}=10.3

  • PR=PT+TR=10.3+17.9=28.2cm

Now

Area:-

\\ \tt\hookrightarrow 1/2bh

\\ \tt\hookrightarrow 1/2(28.2)(9.3)

\\ \tt\hookrightarrow 14.1(9.3)

\\ \tt\hookrightarrow 131.13cm^2

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