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sweet [91]
3 years ago
9

Which are the center and radius of the circle with equation (x + 5)2 + (y - 4)2 = 9?

Mathematics
1 answer:
alina1380 [7]3 years ago
4 0

Answer:

Center (-5,4) radius 3

Step-by-step explanation:

The standard equation of a circle is

(x-h)^2+(y-k)^2=r^2

where the center is (h,k) and r is the radius

so h=-5 in this case and k is 4

r^2=9 so r=3

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Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
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Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

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3 years ago
Evaluate 4y when y = 5
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Step-by-step explanation:

4y

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3 years ago
-13x - 8 = 5 - 8x -3
kramer

Answer:

x = -2

Step-by-step explanation:

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NeX [460]
<span>-34-r=-7(8r-3)
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