Write a linear function whose slope is -4 and y-intercept is -5. Explain what these values mean in the equation

A restaurant has three locations, all about the same size, within the same city. The graph shows last mon's sales figures for on

Liula [17]

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8 0

2 years ago

Find the coordinates of point B along a directed line segment from A(3,4) and

andreev551 [17]

We have been given two points. $A(3,4)$ and $C(3,9)$ . We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.

We will use segment formula to solve our given problem.

When a point P divides segment any segment internally in the ratio $m:n$ , then coordinates of point P are:

$[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]$

$(x_1,y_1)=(3,4)$ and $(x_2,y_2)=(3,9)$ .

$m=4,n=1$

Upon substituting our given information in above formula, we will get:

$[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]$

$[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]$

$[\right x=\frac{15}{5},y=\frac{40}{5}\left]$

$[\right x=3,y=8\left]$

Therefore, the coordinates of point B would be $(3,8)$ .

8 0

3 years ago

The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management

dexar [7]

Answer:

d. 15

Step-by-step explanation:

Putting the values in the shift 2 function

X1 + X2 ≥ 15

where x1= 13, and x2=2

13+12≥ 15

15≥ 15

At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

Now Putting the value X1 ≥ 12 in shift 2 constraint

X1 + X2 ≥ 15

12+ 2≥ 15

14 ≥ 15

this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

gives

X2 ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0

3 years ago

A cylindrical soup can has a diameter of 3.6 in. and is 6.4 in. tall. Find the volume of the can.

arsen [322]

<h2>⚘Your Answer:------</h2>

<h3>Given Information:</h3>

Diameter of can:- 3.6 cm
Height of can:- 6.4 cm

Volume of the Can.

<h3>Solution:</h3>

Radius = (Diameter/2)

ㅤㅤㅤㅤ3.6 cm/2

ㅤㅤㅤㅤ1.8 cm

So, Radius of the soup can is 1.8 cm.

Volume øf cylinder = Volume øf can

Volume of cylinder = π r²h

(π = 22/7)

(r = radius = 1.8 cm)

(h = height = 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7×(1.8 cm)²× 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7× 3.24 cm² × 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7 × 20.736 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= (456.192/7) cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 65.17 cm³

So, the Volume of the soup can is 65.17 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤ⚘Thank You

7 0

2 years ago

Select the denominator of 4/9

Assoli18 [71]

The denominator is the one on the bottom so 9 is the denominator the top is the numerator

5 0

3 years ago