Answer:
Solution given:
1.
diameter(d)=6mm
base(b)=8mm
height (h)=5mm
Area of figure=area of parallelogram +area of semi circle
- base*height+½π(d/2)²
- 8*5+½*π×(6/2)²
- 40+14.14
- 54.4mm²
- <u>Area</u><u> </u><u>:</u><u>5</u><u>4</u><u>.</u><u>1</u><u>4</u><u>m</u><u>m</u><u>²</u>
2.
for triangle
base[b]=6ft
height(h)=9ft
for square
length[l]=9ft
Area of figure=area of square +area of triangle
- =l²+½*b*h
- =9²+½*6*9
- =81+27
- =108ft²
- <u>Area</u><u>:</u><u> </u><u>1</u><u>0</u><u>8</u><u>f</u><u>t</u><u>²</u>
You can not see the problem
Yes you can I hope this helped lol
48 = 2*2*2*2*3
84 = 2*2*3*7
Looking for common factors we get the GCF to be 2*2*3 = 12
Its B
