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enot [183]
3 years ago
10

Find the area of the shaded region.

Mathematics
1 answer:
RoseWind [281]3 years ago
6 0

Answer: 51 in²

Step-by-step explanation: Using the given diagram, we can find the area of the shaded region by taking the area of the larger rectangle minus the area of the area of the small rectangle.

To find the area of the large rectangle, we start with the formula for the area of a rectangle which is shown below.

Area = length · width

Since the length of the large rectangle is 15 in and the width is 5 in, we can plug this information into the formula to get 15 in · 5 in or 75 in.

So the area of the larger rectangle is 75 in.

To find the area of the small rectangle, we also use length · width which is simply 8 in · 3 in or 24 in. So the area of the small rectangle is 24 in.

Finally, remember that  the area of the shaded region is the area of the larger rectangle minus the area of the smaller rectangle which in this case will be 75 - 24 or 51

So the area of the shaded region is 51 in².

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Using elimination (combination), which variable will be eliminated first? 5x-y=-21x+y=-3
stiks02 [169]

Answer:

Option B) The variable Y will cancel out first.

Step-by-step explanation:

we have

5x-y=-21 ----> equation A

x+y=-3 ----> equation B

Solve by elimination

Adds equation A and equation B

5x-y=-21

x+y=-3

--------------

5x+x=-21-3 ----->variable y will be eliminated first

6x=-24

x=-4

7 0
3 years ago
Researchers at the National Cancer Institute released the results of a study that investigated the effect of weed-killing herbic
jolli1 [7]

Answer:

The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

The randomly sampled 400 dogs from homes where an herbicide was used on a regular basis, diagnosing lymphoma in 230 of them.

This means that:

p_h = \frac{230}{400} = 0.575, s_h = \sqrt{\frac{0.575*0.425}{400}} = 0.0247

Of 200 dogs randomly sampled from homes where no herbicides were used, only 25 were found to have lymphoma.

This means that:

p_n = \frac{25}{200} = 0.125, s_n = \sqrt{\frac{0.125*0.875}{200}} = 0.0234

Distribution of the difference:

p = p_h - p_n = 0.575 - 0.125 = 0.45

s = \sqrt{s_h^2+s_n^2} = \sqrt{0.0247^2 + 0.0234^2} = 0.034

Confidence interval:

The confidence interval is:

p \pm zs

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower bound is 0.45 - 1.96(0.034) = 0.3834

The upper bound is 0.45 + 1.96(0.034) = 0.5166

The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

3 0
3 years ago
Links will get banned​
goblinko [34]

Answer:

22 cm long

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4 0
3 years ago
Which statements are true?
castortr0y [4]

Answer:


Step-by-step explanation:i ant see it well try zooming in a little more and i can see


5 0
3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Minchanka [31]

Answer:

Step-by-step explanation:

2k+10   | Both terms share the common factor two, so you can take it out (divide both terms by 2)

2(k+5)  | Now if you use the Distributive Property to double check, you get 2k+ 10 again

4 0
3 years ago
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