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2 years ago

14

Multiply (x^2 - 3x + 4)(-2x^2 + 4x - 1) Show the steps on how to solve please.

1 answer:

Firdavs [7]2 years ago

5 0

-2x^4 + 10x^3 - 21x^2 + 19x - 4

that should be the right answer

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True or False the graph below is a reduction:

ser-zykov [4K]

Answer:

False

Step-by-step explanation:

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2 years ago

Use the law of sines to find the value of w.

Lunna [17]

Option B: 4.0 cm is the value of w

Explanation:

It is given that $\angle W= 39$ , $\angle U=31$ , $VW=3.3$ and $UV=w$

Using the law of sines, we have,

$\frac{sin U}{3.3} =\frac{sin W}{w}$

Substituting the values, we have,

$\frac{\sin 31}{3.3}=\frac{\sin 39}{w}$

Cross multiplying, we get,

$(sin31) w=3.3( \sin 39)$

Simplifying, we have,

$0.515w=2.077$

Dividing both sides by 0.515, we have,

$w=4.0$

Thus, the value of w is 4.0 cm

Hence, Option B is the correct answer.

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2 years ago

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Please help!! What is the slope of the line?

Usimov [2.4K]

Do you have A picture of the line?

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2 years ago

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The bike store marks up the wholesale cost of all of the bikes they sell by 30%.

aev [14]

Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

The wholesale cost or market price of the bike = m.p = $ 96.15

A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 30 % = 1 - $\dfrac{s. p }{m . p}$

or, $\dfrac{30 }{100}$ = 1 - $\dfrac{s. p }{96.15}$

Or, $\dfrac{s. p }{96.15}$ = 1 - $\dfrac{30 }{100}$

or, $\dfrac{s. p }{96.15}$ = $\dfrac{100 - 30 }{100}$

Or, $\dfrac{s. p }{96.15}$ = $\dfrac{70}{100}$

Or, s. p = $\dfrac{70}{100}$ × 96.15

∴ s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30 . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 20 % = 1 - $\dfrac{s. p' }{m . p}$

or, $\dfrac{20 }{100}$ = 1 - $\dfrac{s. p' }{96.15}$

Or, $\dfrac{s. p' }{96.15}$ = 1 - $\dfrac{20 }{100}$

or, $\dfrac{s. p' }{96.15}$ = $\dfrac{100 - 20 }{100}$

Or, $\dfrac{s. p' }{96.15}$ = $\dfrac{80}{100}$

Or, s. p' = $\dfrac{80}{100}$ × 96.15

∴ s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92 . Answer

7 0

2 years ago

Which applies the power of a product rule to simplify (5 t) cubed?

Elena L [17]

Answer:

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed ⇒ 3rd answer

Step-by-step explanation:

Let us revise some rules of exponents

$a^{m}$ × $a^{n}$ = $a^{m+n}$

$a^{m}$ ×÷ $a^{n}$ = $a^{m-n}$

$(a^{m})^{n}$ = $a^{m.n}$

$(a.b)^{m}$ = $a^{m}$ . $b^{m}$

To simplify $(5t)^{3}$

∵ 5t means 5 × t

∵ Both of them are cubed

- Use the 4th rule above

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$

∵ (5)³ = 5 × 5 × 5 = 125

∴ $(5t)^{3}$ = $(5)^{3}.(t)^{3}$ = 125 t³

(5 t ) cubed = 5 cubed . t cubed = 125 t cubed applies the power of a product rule to simplify (5 t) cubed

3 0

3 years ago

Read 2 more answers