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3 years ago

Which of the following is an example of an improper fraction? 3, 9/5, 5/9, 1 1/2

1 answer:

5 0

An improper fraction is when the top number is bigger than the bottom.

So an example of this would be.
9/5
and..
11/2

Good Luck! :)

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(4,-1). Parallel to y=-4x+2

allochka39001 [22]

Answer: x=1/2

Step-by-step explanation:

y= - 4x + 2

X=1/2

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3 years ago

Which point is closest to 6.5?<br> A) A <br> B) B <br> C) C <br> D) D

Illusion [34]

That would be B) B
hope it helps

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3 years ago

Vesnalui [34]

X is 125 as well because it’s an Cubs all sides are equal

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3 years ago

According to data from a medical association, the rate of change in the number of hospital outpatient visits, in millions, in

GaryK [48]

Answer:

a) $f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient visits, in millions, is given by:

$f'(t)=0.001155t(t-1980)^{0.5}$

a) To find the function f(t) you integrate f(t):

$\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt$

To solve the integral you use:

$\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}$

Next, you replace in the integral:

$\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C$

Then, the function f(t) is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'$

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.

Hence C' = 264,034,000

The function is:

$f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000$

b) For t = 2015 you have:

$f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7$

3 0

3 years ago

1. Write two different equations whose solutions are 5 .

vovangra [49]

Two equations that have the solution 5:
3y = 2y + 5
2y - y = -3 + 8

To solve an equation is to isolate a variable and find its specific value.

3 0

3 years ago