Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
<h2>-11 and 1</h2>
Step-by-step explanation:
Put the values of x to the given expression:
for x = -3:
2(-3) - 5 = -6 - 5 = -11
for x = 3
2(3) - 5 = 6 - 5 = 1
Answer:
y= -3/5x+5
Step-by-step explanation:
Answer:
Step-by-step explanation:
In general, given the function, f(x), its zeros can be found by setting the function to zero. The values of x that represent the set equation are the zeroes of the function. To find the zeros of a function, find the values of x where f(x) = 0.
