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grigory [225]
2 years ago
9

Write the numerical expression 34 in expanded form.

Mathematics
1 answer:
garik1379 [7]2 years ago
5 0

Answer:

not sure what type you mean but here are options

Step-by-step explanation:

30+4=34

thirty-four

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What is the range of possible values for x?
Talja [164]
The minimum value for 2x is 0 
<span>the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC </span>
<span>base AB = 52 and vertical angle 2x + 34° </span>

<span>For the sine law </span>
<span>(sin 2x)/22 = (sin ADB)/AB </span>
<span>(sin 34°)/30 = (sin BDC)/BC </span>

<span>is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from </span>
<span>(sin ADC)/AB = (sin BDC)/BC </span>

<span>it follows </span>
<span>(sin 2x)/22 = (sin 34°)/30 </span>

<span>sin 2x = 22 (sin 34°)/30 </span>

<span>2x = asin(22 (sin 34°)/30) ≈ 24.2° </span>

<span>x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1° </span>

<span>0 < x < 12.1°</span>
7 0
3 years ago
Can y’all help with this :)))))
cricket20 [7]
There’s a pattern to this and I’ll explain in the comments if you want to know or can’t figure it out :)


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5.) x^6y^6

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7.) 1,000a^9b^6/a^6b^9

8.) 81x^21/625

9.) 2304/x^16y^12

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12.) x^24y^24/4,096


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7 0
3 years ago
If hexagon JGHFKI Is congruent to hexagon SRTQUV, which pair of angles must be congruent?
Dima020 [189]

Hey there!

If these hexagons are congruent, then each angle is congruent to the one that is in the same position as it is. In this case, I and V are congruent because they are both last. K and U are congruent because they are both second to last.

While looking over the answer options, you should be able to see that Angle J and Angle S is the only answer with angles that match up, because they are both the first angle in the set.

I hope this helps!

3 0
3 years ago
Read 2 more answers
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
Write the ratio of the first measurement to the second measurement. Compare in millimeters.
larisa86 [58]

Answer:

8:19

Step-by-step explanation:

Ball B:  diameter in mm = 9.5 * 10 = 95 mm

Ratio of Ball A to Ball B = 40 : 95

=  8:19 answer

5 0
3 years ago
Read 2 more answers
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