Question

Factor 125x9 64. (5x3 – 4)(25x6 20x3 16) (5x3 – 4)(25x3 20x3 16) (5x3 4)(25x6 – 20x3 16) (5x3 4)(25x3 – 20x3 16).

Answer 1

The factorization of $\rm 125x^9 + 64$ is  $\rm (5x^3 + 4)(25x^6 - 20x^3 +16)$.

Factorization;

Factorization is nothing but writing a number as the product of smaller numbers.

Given

Polynomial; $\rm 125x^9 + 64$

To find the factorization the polynomial equates the equation with zero following all the steps given below.

Then,

The factor of the polynomial is;

$\rm= 125x^9 + 64\\\\= 125x^9 -100x^6+80x^3+100x^6-80x^3+64 \\\\ =5x^3(25x^6 - 20x^3 +16) +4(25x^6 - 20x^3 +16) \\\\=(5x^3 + 4)(25x^6 - 20x^3 +16)$

Hence, the factorization of $\rm 125x^9 + 64$ is  $\rm (5x^3 + 4)(25x^6 - 20x^3 +16)$.

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