The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
Answer:
A. Is ll and lll
B. ll only
C. l and ll
Step-by-step explanation:
Answer:
y= 0.8x
Step-by-step explanation:
1/7x - 6 = 8(11-3)
1/7x - 6 = 8(8)
1/7x - 6 = 64
1/7x = 70
1/7 = 70x
1 = 490x
1/490 = x
