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lisov135 [29]
4 years ago
9

Which choice is equivalent to the quotient shown here for acceptable values of x?

Mathematics
2 answers:
snow_tiger [21]4 years ago
6 0

Answer:

Choice D

Step-by-step explanation:

The division of the two radicals can be re-written in the following format;

\frac{\sqrt{30(x-1)} }{\sqrt{5(x-1)^{2} } }

Using the properties of radicals division, the expression can further be written as;

\sqrt{\frac{30(x-1)}{5(x-1)^{2} } }

We simplify the terms under the radical sign to obtain;

\sqrt{\frac{6}{x-1} }

Choice D is thus the correct solution

Degger [83]4 years ago
3 0

Answer: OPTION D

Step-by-step explanation:

You need to remember this property:

\frac{\sqrt{x} }{\sqrt{y} }=\sqrt{\frac{x}{y} }

And remember that:

\frac{a}{a}=1

Then, the first step is rewrite the expression:

\frac{\sqrt{30(x-1)} }{\sqrt{5(x-1)^2}} =\sqrt{\frac{30(x-1)}{5(x-1)^2}} }

Now, to find the corresponding equivalent expression, you need to simplify the expression.

Therefore, the equivalent expression is the following:

\sqrt{\frac{6}{(x-1)}} }

Finally, you can observe that this matches with the option D.

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