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inna [77]
2 years ago
14

Factor -6g + 9g. 6(g + 9) -g(6 – 9) -g(6 + 9) g(6 + 9)

Mathematics
2 answers:
Olin [163]2 years ago
7 0

Answer:g(−219.6g+45.6)

Step-by-step explanation:

−6g+9g(0.6)(g+9)−g(6−9)−g(6+9)g(6+9)

−219.6g2+45.6g

=g(−219.6g+45.6)

blsea [12.9K]2 years ago
6 0

Answer:

-225g^2-3g+9g^{1.6}+81g^{0.6}

Step-by-step explanation:

=-6g+9g^{0.6}\left(g+9\right)-\left(-3g\right)-15^2g^2

15^2=225

=-6g+9g^{0.6}\left(g+9\right)+3g-225g^2

-6g+9g^{1.6}+81g^{0.6}+g\cdot \:3-g^2\cdot \:225

-225g^2-3g+9g^{1.6}+81g^{0.6}

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Answer:

Step-by-step explanation:

Given

Points (-1,7) and (1,3)

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m = (y2 = y1) / (x2 - x1)

y2 = 7

y1 = 3

x2 = - 1

x1 = 1

Solution

m = (7 - 3) / (-1 - 1)

m = 4 / - 2

m = - 2

Now use either one of the points to get b in y = mx + b

x = 1

y = 3

m = - 2

y = mx + b

3 = -2 (1) + b

3 = -2 + b

b = 3 + 2

b = 5

Equation: y = - 2x + 5

Second question.

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2 years ago
Of a classroom filled with 20 students, 2 will be selected to stay after school and correct homework for extra credit. How
Tcecarenko [31]

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3 0
3 years ago
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What is the remainder when (x3 + 1) is divided by (x2 – x + 1)? x + 1 x 2 0
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Find the value of x if a,b, and c are collinear points an b is between a and c
MakcuM [25]
\sf Hello!

• \sf AB = x + 6
• \sf BC = 3x - 5
• \sf AC = 36 - x

\sf We're \:given\: that \:A,\: B\: and \:C \:are \:Collinear\: points

\sf Then,

\sf AB + BC = AC

⇒ \sf x + 6 + 3x - 5 = 36 - x

⇒ \sf x + 3x + 6 - 5 = 36 - x

⇒ \sf 4x + 1 = 36 - x

⇒ \sf 4x + x = 36 - 1

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\sf Hence,

\sf The\: value\: of\: x\: is\: D.\: 7

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3 years ago
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