Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:
2 solutions; x=2.5 x=-25
Step-by-step explanation:
16x^2 = 100
x^2 = 100/16
x^2 = 6.25
x = (+-) sqrt 6.25
x = (+-) 2.5
Answer:
B. c = fλ
Step-by-step explanation:
The given equation is

To solve for c you must multiply both sides of the equation by lambda.

Answer:
607,261
Step-by-step explanation:
Okay, So you have 24x+25=6y+7
Step 1: Pull out like factors : 24x + 18 + 6y = 6 • (4x + y + 3)
Step 2: 4x+y+3 = 0
y-intercept = -3/1 = -3.00000
x-intercept = -3/4 = -0.75000
Slope = -8.000/2.000 = -4.000
And bam, you have a straight line