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inna [77]
2 years ago
14

Factor -6g + 9g. 6(g + 9) -g(6 – 9) -g(6 + 9) g(6 + 9)

Mathematics
2 answers:
Olin [163]2 years ago
7 0

Answer:g(−219.6g+45.6)

Step-by-step explanation:

−6g+9g(0.6)(g+9)−g(6−9)−g(6+9)g(6+9)

−219.6g2+45.6g

=g(−219.6g+45.6)

blsea [12.9K]2 years ago
6 0

Answer:

-225g^2-3g+9g^{1.6}+81g^{0.6}

Step-by-step explanation:

=-6g+9g^{0.6}\left(g+9\right)-\left(-3g\right)-15^2g^2

15^2=225

=-6g+9g^{0.6}\left(g+9\right)+3g-225g^2

-6g+9g^{1.6}+81g^{0.6}+g\cdot \:3-g^2\cdot \:225

-225g^2-3g+9g^{1.6}+81g^{0.6}

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Work out the area of this circle. Take pie to be 3.142 and give your answer to 2 decimal places.

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Right triangle FHG is shown. The sine of angle F is 0.53. What is the cosine of Angle h ?
g100num [7]

<u>Given</u>:

Given that FGH is a right triangle. The sine of angle F is 0.53.

We need to determine the cosine of angle H.

<u>Cosine of angle H:</u>

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This can be written as,

sin F=0.53

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\frac{HG}{FH}=0.53 ----- (1)

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20
Alenkinab [10]

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Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }

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= \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= { (x-1)(x+4)}

= { x^2+3x-4}

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3 years ago
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