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ella [17]
3 years ago
8

A coffee seller makes a salary of 3,500 dollars per month plus $12 commission for every $100 of coffee he sells. a case of coffe

e costs $25.
how many cases of coffee did he sell if his pay at the end of the month is 3,650?
Mathematics
2 answers:
Murljashka [212]3 years ago
8 0

Answer:

50 cases

Step-by-step explanation:

QveST [7]3 years ago
3 0

Th coffee seller must have sold 130 coffee case but for him to make at least $3650, he must've sold 131 cups of coffee

Data;

  • monthly salary = $3500
  • commission = $12
  • amount due for commission = $100
  • cost of coffee = $25
  • total amount = $3650

<h3>Word Problem</h3>

These are verbal expressions used to represent mathematical problems and if we want to solve them, we must translate them into equations.

If his total pay is $3650 and he earns a commission of $12 for every $100 coffee sold.

How many coffee case are inside $100

100/25=4

This shows that for every 4 coffee case sold, she made ($100 + $12) as profit.

If 4 coffee = $112

how many coffee will give us $3650

4coffee=$112\\x coffee = $3650\\x = \frac{4*3650}{112} \\x = 130.35

From the calculations above, he must've sold at least 131 cups of coffee to make $3650.

Learn more on word problems here;

brainly.com/question/21405634

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Kaylis [27]

Answer:

A) The expression for the number of bacteria is P(t) = 400e^{0.7783t}.

B) After 5 hours there will be 19593 bacteria.

C) After 5.55 hours the population of bacteria will reach 30000.

Step-by-step explanation:

A) Here we have a problem with differential equations. Recall that we can interpret the rate of change of a magnitude as its derivative. So, as the rate change proportionally to the size of the population, we have

P' = kP

where P stands for the population of bacteria.

Writing P' as \frac{dP}{dt}, we get

\frac{dP}{dt} = kP.

Notice that this is a separable equation, so

\frac{dP}{P} = kdt.

Then, integrating in both sides of the equality:

\int\frac{dP}{P} = \int kdt.

We have,

\ln P = kt+C.

Now, taking exponential

P(t) = Ce^{kt}.

The next step is to find the value for the constant C. We do this using the initial condition P(0)=400. Recall that this is the initial population of bacteria. So,

400 = P(0) = Ce^{k0}=C.

Hence, the expression becomes

P(t) = 400e^{kt}.

Now, we find the value for k. We are going to use that P(4)=9000. Notice that

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Then,

\frac{90}{4} = e^{4k}.

Taking logarithm

\ln\frac{90}{4} = 4k, so \frac{1}{4}\ln\frac{90}{4} = k.

So, k=0.7783788273, and approximating to the fourth decimal place we can take k=0.7783. Hence,

P(t) = 400e^{0.7783t}.

B) To find the number of bacteria after 5 hours, we only need to evaluate the expression we have obtained in the previous exercise:

P(5) =400e^{0.7783*5} = 19593.723 \approx 19593.  

C) In this case we want to do the reverse operation: we want to find the value of t such that

30000 = 400e^{0.7783t}.

This expression is equivalent to

75 = e^{0.7783t}.

Now, taking logarithm we have

\ln 75 = 0.7783t.

Finally,

t = \frac{\ln 75}{0.7783} \approx 5.55.

So, after 5.55 hours the population of bacteria will reach 30000.

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Answer:

The correct answer is (A).

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Because the data came from 3 groups in a randomized experiment, the appropriate test is a chi-square test for homogeneity.

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Mitch's father needs 1 1\2 tons of gravel.He bought 1,750 pounds of gravel.How many more pounds of gravel does he need
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poizon [28]

Answer and Step-by-step explanation:

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All number of the form 2n, n is the natural number under multiplication is not a group. Because its inverse does not exist. For example, an element x belongs to a natural number; its inverse (1/x) does not exist in this set.

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sertanlavr [38]

Answer:

1

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-4 + 5

1

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3 years ago
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