The graph of a quadratic f(x) intersects the x-axis at –15 and 9. What is a possible

1 answer:

5 0

the point that the function intercepts the x axis are the zeros of the function, where the products set equal to zero give you the x coordinate in which it intercepts.

x=-15 and x=9

set both equal to 0

x+15 and x-9

These are your two products

(x+15)(x-9)

x^2+6x-135

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Gala2k [10]

If you're factoring, your answer is

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You'll work it out this way:

16x^2 + 8x - 15

Since there's no GCF here, you multiply the first and third terms, giving you -240. Your next step is to find two numbers that have a sum of 8 and a product of -240. These numbers are 20 and -12. Plug those in and you've got:

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Then you group what's outside of the parentheses together (4x - 3)
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