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3 years ago

I need help trying to find out what is 73% of 83?

Mathematics

2 answers:

Ymorist [56]3 years ago

7 0

Answer:

60.59

Step-by-step explanation:

73%=0.73

0.73*83=60.59

ludmilkaskok [199]3 years ago

7 0

60.59 is the number you're looking for.

Hope this helps, if not, comment below please!!!!

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Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi. The distances, m

Mazyrski [523]

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

$\dfrac{845}{1160}=\dfrac{169}{232}.$

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

$\dfrac{116.5}{174}=\dfrac{233}{348}\neq \dfrac{169}{232}$

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

$\dfrac{42.25}{58}=\dfrac{845}{1160}=\dfrac{169}{232}$

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

$\dfrac{23.4}{29}=\dfrac{117}{145}\neq \dfrac{169}{232}$

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

$\dfrac{16.9}{23.2}=\dfrac{169}{232}$

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

$\dfrac{25.35}{34.8}=\dfrac{507}{696}=\dfrac{169}{232}$

This option is true.

Answer: correct options are B, D and E

8 0

3 years ago

Read 2 more answers

Given A(0,-4), B(0,-9), and C(-2,-5). Find the length of BC.

Ivan

Answer:

4.5

Step-by-step explanation:

B(0,-9)

C(-2,-5)

=> BC = $\sqrt{(-2-0)^{2} -(-5+9)^{2} } = 4.4721$

5 0

2 years ago

673 divided by blank = 0.673. What is blank?

OverLord2011 [107]

Answer:

1000

Step-by-step explanation:

5 0

3 years ago

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Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side

maria [59]

Answer:

cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = $-\frac{1}{3}$

cos(b) = $-\frac{1}{4}$

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = $-\sqrt{1-(-\frac{1}{3})^2}$ [Since, sin(a) = $\sqrt{(1-\text{cos}^2a)}$ ]

= $-\sqrt{\frac{8}{9}}$

= $-\frac{2\sqrt{2}}{3}$

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be negative.

sin(b) = $-\sqrt{1-(-\frac{1}{4})^2}$

= $-\sqrt{\frac{15}{16}}$

= $-\frac{\sqrt{15}}{4}$

By substituting these values in the identity,

cos(a + b) = $(-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})$

= $\frac{1}{12}-\frac{\sqrt{120}}{12}$

= $\frac{1}{12}(1-\sqrt{120})$

= $\frac{1}{12}(1-2\sqrt{30})$

Therefore, cos(a + b) = $\frac{1}{12}(1-2\sqrt{30})$

5 0

3 years ago

Factor completely: −2x3 + 6x2

Pavel [41]

Correct answer is C.

$-2x^3+6x^2 \\-2x^2x+2x^23 \\2x^2(-x+3) \\2x^2(-(x-3)) \\-2x^2(x-3)$

4 0

3 years ago