I’m pretty sure the answer is 50
Length x width equals area of rectangle. 301/2÷61/2=5
the width of the rectangle equals 5 inches.
Answer:
7
Step-by-step explanation:
we use Pythagorean theorem for solving x
a^2 + b^2 = c^2
c^2 - a^2 = b^2
(√58)^2 - (3)^2 = b^2
58 - 9 = b^2
49 = b^2
b = 7
A table will have a length and width, so the area will be just that, the product of those two factors, so in short, simply factor the area of x²+7x-30.
now, if we do a "prime factoring" of 30, we get 2*3*5, and we can mix them as 2*5 and 3, to get the factors of (x² + 10)(x²-3).
If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
<span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
= cos^2 θ / sin^2 θ + 1
= cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
= csc^2 θ
Answers: -1
csc^2 θ