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Gemiola [76]
3 years ago
8

Https://brainly.com/question/22777864 pls help

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0

Answer:

hey

Step-by-step explanation:

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What is the area, in square centimeters, of the isosceles trapezoid below?
cluponka [151]

Answer:

The Area=122.4^2

7 0
3 years ago
Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
3 years ago
Not too sure how to do this equation its on the attached file
Akimi4 [234]

Answer:

The answer is 72

Step-by-step explanation:

Hope this helps :))

6 0
3 years ago
The following graph shows the relationship between cost and revenue for a manufacturer of lab coats.
nataly862011 [7]

Answer:

Option a.

I and III

Step-by-step explanation:

Observing the graph

For n=400 coats

The cost is about $2,200

and

The revenue is less than $1,400

Substitute the value of n=400 in each equation to find the solution

I Cost 1.5(400)+1,600=$2,200 ----> is ok

II Cost 4.5(400)+1,600=$3,400 ----> is not ok ( is greater than $2,200)

III Revenue 3.25(400)=$1,300 ----> is ok ( is less than $1,400)

IV Revenue 5.75(400)=$2,300 ----> is not ok ( is greater than $1,400)

therefore

The solution is I and III

6 0
3 years ago
Read 2 more answers
4) Stan owns 4 5 of an acre of land. Of that, 2 3 of the land is fenced. How many acres of land is fenced? A
sergeinik [125]
(4/5)(2/3)=8/15 acre
4 0
3 years ago
Read 2 more answers
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