What would the adverage be of 12 and 13 if thats possible to find one?
1 answer:
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X intercept: when Y = 0
Y intercept: when X = 0
Plug into equation
4x + 6(0) = 12
4x = 12, x = 3
Therefore x int = (3,0)
4(0) + 6y = 12
6y = 12, y = 2
Therefore y int = (0,2)
Plug those points then draw a line through them
Y intercept: when X = 0
Plug into equation
4x + 6(0) = 12
4x = 12, x = 3
Therefore x int = (3,0)
4(0) + 6y = 12
6y = 12, y = 2
Therefore y int = (0,2)
Plug those points then draw a line through them