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Ahat [919]
3 years ago
12

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
kompoz [17]3 years ago
8 0

Answer: C

<u>Step-by-step explanation:</u>

Use the multiplication rule for matrices - Multiply 1st row of first matrix with 1st column of second matrix and find their sum. Repeat for each row and column.

      A        x        B

\left[\begin{array}{cc}1&5\\-3&4\end{array}\right] \times \left[\begin{array}{cc}2&6\\6&-1\end{array}\right]=\left[\begin{array}{cc}1(2)+5(6)&1(6)+5(-1)\\-3(2)+4(6)&-3(6)+4(-1)\end{array}\right]\\\\\\.\qquad \qquad \qquad \qquad \qquad \quad =\left[\begin{array}{cc}32&1\\18&-22\end{array}\right]

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4 years ago
Please helppp with this math question &lt;333
Naya [18.7K]

Answer:

The average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

Step-by-step explanation:

We are given the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1

We need to find average rate of change.

The formula used to find average rate of change is : Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}

We have b=-1 and a=-11

Finding g(b) = g(-1)

g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9

Finding g(a) = g(-11)

g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29

Finding average rate of change

Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1

So, the average rate of change of the function g(x)=x^2+10x+18 over the interval -11 \leq x\leq -1 is -1

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